$ character represents the process ID number, or PID, of the current shell:
$echo $$
Above command would write PID of the current shell:
29949
The following table shows a number of special variables that you can use in your shell scripts:
Variable | Description |
$0 | The filename of the current script. |
$n | These variables correspond to the arguments
with which a script was invoked. Here n is a positive decimal number
corresponding to the position of an argument (the first argument is $1,
the second argument is $2, and so on). |
$# | The number of arguments supplied to a script. |
$* | All the arguments are double quoted. If a script receives two arguments, $* is equivalent to $1 $2. |
$@ | All the arguments are individually double quoted. If a script receives two arguments, $@ is equivalent to $1 $2. |
$? | The exit status of the last command executed. |
$$ | The process number of the current shell. For shell scripts, this is the process ID under which they are executing. |
$! | The process number of the last background command. |
Command-Line Arguments:
The command-line arguments $1, $2, $3,...$9 are positional
parameters, with $0 pointing to the actual command, program, shell
script, or function and $1, $2, $3, ...$9 as the arguments to the
command.
Following script uses various special variables related to command line:
#!/bin/sh
echo "File Name: $0"
echo "First Parameter : $1"
echo "First Parameter : $2"
echo "Quoted Values: $@"
echo "Quoted Values: $*"
echo "Total Number of Parameters : $#"
Here is a sample run for the above script:
$./test.sh Zara Ali
File Name : ./test.sh
First Parameter : Zara
First Parameter : Ali
Quoted Values: Zara Ali
Quoted Values: Zara Ali
Total Number of Parameters : 2
Special Parameters $* and $@:
There are special parameters that allow accessing all of the
command-line arguments at once. $* and $@ both will act the same unless
they are enclosed in double quotes,
"".
Both the parameter specifies all command-line arguments but the "$*"
special parameter takes the entire list as one argument with spaces
between and the "$@" special parameter takes the entire list and
separates it into separate arguments.
We can write the shell script shown below to process an unknown
number of command-line arguments with either the $* or $@ special
parameters:
#!/bin/sh
for TOKEN in $*
do
echo $TOKEN
done
There is one sample run for the above script:
$./test.sh Zara Ali 10 Years Old
Zara
Ali
10
Years
Old
Note: Here do...done is a kind of loop which we would cover in subsequent tutorial.
Exit Status:
The $? variable represents the exit status of the previous command.
Exit status is a numerical value returned by every command upon its
completion. As a rule, most commands return an exit status of 0 if they
were successful, and 1 if they were unsuccessful.
Some commands return additional exit statuses for particular reasons.
For example, some commands differentiate between kinds of errors and
will return various exit values depending on the specific type of
failure.
Following is the example of successful command:
$./test.sh Zara Ali
File Name : ./test.sh
First Parameter : Zara
First Parameter : Ali
Quoted Values: Zara Ali
Quoted Values: Zara Ali
Total Number of Parameters : 2
$echo $?
0
$